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Questions10
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1

Find the side of a Triangle whose perimeter is 28 in

9 in ? 9 in

Perimeter = 28 in

2

Find the side of a Parallelogram whose perimeter is 18 in

? 3 in6 in3 in

Perimeter = 18 in

3

Find the side of a Pentagon whose perimeter is 15 in

?

Perimeter = 15 in

4

Find the side of a Rectangle whose area is 45 in^{2}

? 5 in

Area = 45 in^{2}

5

Find the side of a Square whose area is 100 in^{2}

?

Area = 100 in^{2}

6

Find the side of a Square whose area is 49 in^{2}

?

Area = 49 in^{2}

7

Find the side of a Rectangle whose area is 60 in^{2}

10 in ?

Area = 60 in^{2}

8

Find the side of a Trapezoid whose perimeter is 18 in

3 in2 in ? 10 in

Perimeter = 18 in

9

Find the Radius of a Circle whose area is 37.68 in^{2}

?

Perimeter = 37.68 in

10

Find the Radius of a Circle whose area is 43.96 in^{2}

?

Perimeter = 43.96 in

Answers Key

Show All Workout

1

Find the side of a Triangle whose perimeter is 28 in

9 in10 in9 in

Perimeter = 28 in

Solution

Perimeter = Sum of the measure of all the sides.

Perimeter = side1 + side2 + side3.

Perimeter = 28 in

side2 = 9 in

side3 = 9 in

To find side3,

side1 = Perimeter - (side2 + side3)

side1 = 28 - (9 + 9)

∴ side1 = 10 in

Perimeter = side1 + side2 + side3.

Perimeter = 28 in

side2 = 9 in

side3 = 9 in

To find side3,

side1 = Perimeter - (side2 + side3)

side1 = 28 - (9 + 9)

∴ side1 = 10 in

2

Find the side of a Parallelogram whose perimeter is 18 in

6 in3 in6 in3 in

Perimeter = 18 in

Solution

Perimeter = Sum of the measure of all the sides.

Perimeter = side1 + side2 + side3 + side4.

Perimeter = 18 in

side1 = 6 in

side2 = 3 in

side4 = 3 in

To find side3,

side3 = Perimeter - (side1 + side2 + side4)

side3 = 18 - (6 + 3 + 3)

∴ side3 = 6 in

Perimeter = side1 + side2 + side3 + side4.

Perimeter = 18 in

side1 = 6 in

side2 = 3 in

side4 = 3 in

To find side3,

side3 = Perimeter - (side1 + side2 + side4)

side3 = 18 - (6 + 3 + 3)

∴ side3 = 6 in

3

Find the side of a Pentagon whose perimeter is 15 in

3 in

Perimeter = 15 in

Solution

pentagon has 5 sides,and all side have equal length

Perimeter = 5 x side

To find side,Perimeter = 15 in∴ = 3 in

Perimeter = 5 x side

To find side,

side =

Perimeter5

side =

155

4

Find the side of a Rectangle whose area is 45 in^{2}

9 in5 in

Area = 45 in^{2}

Solution

To find length,

Area = 45 in^{2}

Breadth (b) = 5 in

Area = l x b

∴ Length (l) = 9 in

Area = 45 in

Breadth (b) = 5 in

Area = l x b

l =

Areab

Length (l) =

455

5

Find the side of a Square whose area is 100 in^{2}

10 in

Area = 100 in^{2}

Solution

To find side,

Area = 100 in^{2}

Area = side^{2}

side = √area

side = √100

∴ side = 10 in

Area = 100 in

Area = side

side = √area

side = √100

∴ side = 10 in

6

Find the side of a Square whose area is 49 in^{2}

7 in

Area = 49 in^{2}

Solution

To find side,

Area = 49 in^{2}

Area = side^{2}

side = √area

side = √49

∴ side = 7 in

Area = 49 in

Area = side

side = √area

side = √49

∴ side = 7 in

7

Find the side of a Rectangle whose area is 60 in^{2}

10 in6 in

Area = 60 in^{2}

Solution

To find breadth,

Area = 60 in^{2}

Length (l) = 10 in

Area = l x b

∴ Breadth (b) = 6 in

Area = 60 in

Length (l) = 10 in

Area = l x b

b =

Areal

Breadth (b) =

6010

8

Find the side of a Trapezoid whose perimeter is 18 in

3 in2 in3 in10 in

Perimeter = 18 in

Solution

Perimeter = Sum of the measure of all the sides.

Perimeter = side1 + side2 + side3 + side4.

Perimeter = 18 in

side1 = 3 in

side3 = 10 in

side4 = 2 in

To find side4,

side2 = Perimeter - (side1 + side3 + side4)

side2 = 18 - (3 + 2 + 10)

∴ side2 = 3 in

Perimeter = side1 + side2 + side3 + side4.

Perimeter = 18 in

side1 = 3 in

side3 = 10 in

side4 = 2 in

To find side4,

side2 = Perimeter - (side1 + side3 + side4)

side2 = 18 - (3 + 2 + 10)

∴ side2 = 3 in

9

Find the Radius of a Circle whose area is 37.68 in^{2}

6 in

Perimeter = 37.68 in

Solution

To find radius,

Perimeter = 37.68 in

Perimeter = 2 x π x r

∴ Radius(r) = 6 in

Perimeter = 37.68 in

Perimeter = 2 x π x r

Radius (r) =

Perimeter2 x π

Radius (r) =

37.682 x 3.14

; where π = 3.14

10

Find the Radius of a Circle whose area is 43.96 in^{2}

7 in

Perimeter = 43.96 in

Solution

To find radius,

Perimeter = 43.96 in

Perimeter = 2 x π x r

∴ Radius(r) = 7 in

Perimeter = 43.96 in

Perimeter = 2 x π x r

Radius (r) =

Perimeter2 x π

Radius (r) =

43.962 x 3.14

; where π = 3.14